Factorize the following polynomial: p(x) = x^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To factorize the quadratic polynomial $p(x) = x^{2} + 5x - 24$,we need to find two numbers whose product is $-24$ and whose sum is $5$.These two n

Vedclass · Accepted Answer

$(x + 8)(x - 3)$

Vedclass · Answer

(D) To factorize the quadratic polynomial $p(x) = x^{2} + 5x - 24$,we need to find two numbers whose product is $-24$ and whose sum is $5$.These two numbers are $8$ and $-3$,because $8 	imes (-3) = -24$ and $8 + (-3) = 5$.Now,split the middle term $5x$ as $8x - 3x$:$p(x) = x^{2} + 8x - 3x - 24$Group the terms:$p(x) = (x^{2} + 8x) - (3x + 24)$Factor out the common terms:$p(x) = x(x + 8) - 3(x + 8)$Finally,factor out the common binomial $(x + 8)$:$p(x) = (x + 8)(x - 3)$

Factorize the following polynomial: $p(x) = x^{2} + 5x - 24$

Similar Questions

Find the zeros of the following quadratic polynomial: $15x^2 + 16x + 4$.

Divide $x^{6}+5 x^{3}+7 x+3$ by $x^{2}+2$.

The number of the zeros of $p(x) = x^{2} - 9$ is............

From the given figure,find the number of zeros of $y=p(x)$.

If $-2$ is a zero of the cubic polynomial $p(x) = x^3 + 6x^2 + 11x + 6$,then find the remaining zeros of $p(x)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module